6(t-2)^2+17(t-2)=-12

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Solution for 6(t-2)^2+17(t-2)=-12 equation: 



6(t-2)^2+17(t-2)=-12

We move all terms to the left:

6(t-2)^2+17(t-2)-(-12)=0

We add all the numbers together, and all the variables

6(t-2)^2+17(t-2)+12=0

We multiply parentheses

6(t-2)^2+17t-34+12=0

We add all the numbers together, and all the variables

17t+6(t-2)^2-22=0

We move all terms containing t to the left, all other terms to the right

17t+6(t-2)^2=22

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